(5x^2-3x+4)+(6x-3x^2-3=)

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Solution for (5x^2-3x+4)+(6x-3x^2-3=) equation: 



(5x^2-3x+4)+(6x-3x^2-3=)

We move all terms to the left:

(5x^2-3x+4)+(6x-3x^2-3-())=0

We get rid of parentheses

(6x-3x^2-3-())+5x^2-3x+4=0



We calculate terms in parentheses: +(6x-3x^2-3-()), so:

6x-3x^2-3-()

determiningTheFunctionDomain
-3x^2+6x-3-()

We add all the numbers together, and all the variables

-3x^2+6x

Back to the equation:

+(-3x^2+6x)



We add all the numbers together, and all the variables

5x^2+(-3x^2+6x)-3x+4=0

We get rid of parentheses

5x^2-3x^2+6x-3x+4=0

We add all the numbers together, and all the variables

2x^2+3x+4=0

a = 2; b = 3; c = +4;
Δ = b2-4ac
Δ = 32-4·2·4
Δ = -23
Delta is less than zero, so there is no solution for the equation

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